What is the integral from-1 to 1 of 1/(x+2) ?

The integral from-1 to 1 of 1/(x+2) is ln(3)

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integral from-1 to 1 of 1/(x+2)

\int_{- 1}^{1} \frac{1}{x + 2} d x

ln (3)

Decimal

1.09861 \dots

Solution steps

\int_{- 1}^{1} \frac{1}{x + 2} d x

Apply u-substitution

= \int_{1}^{3} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{1}^{3}

Compute the boundaries:

ln (3)

= ln (3)

What is the integral from-1 to 1 of 1/(x+2) ?
The integral from-1 to 1 of 1/(x+2) is ln(3)