derivative of 1+1/(2x)

解答

\frac{d}{d x} (1 + \frac{1}{2 x})

- \frac{1}{2 x ^{2}}

求解步骤

\frac{d}{d x} (1 + \frac{1}{2 x})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (\frac{1}{2 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

= 0 - \frac{1}{2 x ^{2}}

化简

= - \frac{1}{2 x ^{2}}

d er i v a t i v e y = \frac{x - 5}{x + 5}

\frac{d}{d x} ((2 x + 1)^{2} 3 (2 x + 1) + 10)

in v erse l a pl a ce \frac{1}{s ^{2} - s + 1}

n = 0 \sum \infty 7 (\frac{2}{3})^{n}

\int (x^{3} + 1)^{2} x d x