What is (\partial)/(\partial x)(xy-x+y) ?

The answer to (\partial)/(\partial x)(xy-x+y) is y-1

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(\partial)/(\partial x)(xy-x+y)

\frac{\partial}{\partial x} (x y - x + y)

y - 1

Solution steps

\frac{\partial}{\partial x} (x y - x + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= y - 1 + 0

Simplify

= y - 1

What is (\partial)/(\partial x)(xy-x+y) ?
The answer to (\partial)/(\partial x)(xy-x+y) is y-1