What is the tangent of f(x)= 1/(2+3x),(1, 1/5) ?

The tangent of f(x)= 1/(2+3x),(1, 1/5) is y=-3/25 x+8/25

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tangent of f(x)= 1/(2+3x),(1, 1/5)

tangent of

f (x) = \frac{1}{2 + 3 x}, (1, \frac{1}{5})

y = - \frac{3}{25} x + \frac{8}{25}

Solution steps

Find the slope of

f (x) = \frac{1}{2 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 2 + 3 x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{25}

Find the line with slope m=

- \frac{3}{25}

and passing through

(1, \frac{1}{5}) : y = - \frac{3}{25} x + \frac{8}{25}

y = - \frac{3}{25} x + \frac{8}{25}

What is the tangent of f(x)= 1/(2+3x),(1, 1/5) ?
The tangent of f(x)= 1/(2+3x),(1, 1/5) is y=-3/25 x+8/25