y^{''}=3t^2

Lösung

y^{^{''}} = 3 t^{2}

y = \frac{t ^{4}}{4} + c_{1} t + c_{2}

Schritte zur Lösung

y^{''} (t) = 3 t^{2}

Löse

y^{''} (t) = 3 t^{2} : y^{'} (t) = t^{3} + c_{1}

Löse

y^{'} (t) = t^{3} + c_{1} : y = \frac{t ^{4}}{4} + c_{1} t + c_{2}

y = \frac{t ^{4}}{4} + c_{1} t + c_{2}

\int e^{(- s t)} d t

y^{^{''}} + 4 y = sin (3 x)

t an g e n t f (x) = x^{2} + 1, (2, 5)

\int \frac{2}{1 + 9 x ^{2}} d x

d er i v a t i v e (x^{2} - 1)^{2}