What is the integral from 0 to 1 of (x+7)(x-8) ?

The integral from 0 to 1 of (x+7)(x-8) is -337/6

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integral from 0 to 1 of (x+7)(x-8)

\int_{0}^{1} (x + 7) (x - 8) d x

- \frac{337}{6}

Decimal

- 56.16666 \dots

Solution steps

\int_{0}^{1} (x + 7) (x - 8) d x

Expand

(x + 7) (x - 8) : x^{2} - x - 56

= \int_{0}^{1} x^{2} - x - 56 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x - \int_{0}^{1} x d x - \int_{0}^{1} 56 d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} 56 d x = 56

= \frac{1}{3} - \frac{1}{2} - 56

Simplify

\frac{1}{3} - \frac{1}{2} - 56 : - \frac{337}{6}

= - \frac{337}{6}

What is the integral from 0 to 1 of (x+7)(x-8) ?
The integral from 0 to 1 of (x+7)(x-8) is -337/6