What is the derivative of (x-2^2+2) ?

The derivative of (x-2^2+2) is 2x-4

What is the first derivative of (x-2^2+2) ?

The first derivative of (x-2^2+2) is 2x-4

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\frac{d}{d x} ((x - 2)^{2} + 2)

2 x - 4

Solution steps

\frac{d}{d x} ((x - 2)^{2} + 2)

Simplify

(x - 2)^{2} + 2 : x^{2} - 4 x + 6

= \frac{d}{d x} (x^{2} - 4 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (6) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

What is the derivative of (x-2^2+2) ?
The derivative of (x-2^2+2) is 2x-4
What is the first derivative of (x-2^2+2) ?
The first derivative of (x-2^2+2) is 2x-4