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Popular Calculus >

y^'=(y+sqrt(x^2-y^2))/x

Solution

y^{^{'}} = \frac{y + x ^{2} - y ^{2}}{x}

Solution

y = sin (ln (x) + c_{1}) x

Solution steps

y^{'} (x) = \frac{y + x ^{2} - y ^{2}}{x}

Solve using substitution:

y = sin (ln (x) + c_{1}) x

y = sin (ln (x) + c_{1}) x

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(y+sqrt(x^2-y^2))/x ?
The solution for y^'=(y+sqrt(x^2-y^2))/x is y=sin(ln(x)+c_{1})x