What is the tangent of y= x/(sqrt(9+x^2)),(0,0) ?

The tangent of y= x/(sqrt(9+x^2)),(0,0) is y= 1/3 x

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tangent of y= x/(sqrt(9+x^2)),(0,0)

tangent of

y = \frac{x}{9 + x ^{2}}, (0, 0)

y = \frac{1}{3} x

Solution steps

Find the slope of

y = \frac{x}{9 + x ^{2}} : \frac{d y}{d x} = \frac{9}{( 9 + x ^{2} ) 9 + x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(0, 0) : y = \frac{1}{3} x

y = \frac{1}{3} x

What is the tangent of y= x/(sqrt(9+x^2)),(0,0) ?
The tangent of y= x/(sqrt(9+x^2)),(0,0) is y= 1/3 x