What is the tangent of f(x)=2x^3-x^2+2,\at x=1 ?

The tangent of f(x)=2x^3-x^2+2,\at x=1 is y=4x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=2x^3-x^2+2,\at x=1

tangent of

f (x) = 2 x^{3} - x^{2} + 2, at x = 1

y = 4 x - 1

Solution steps

Find the tangent point:

(1, 3)

Find the slope of

f (x) = 2 x^{3} - x^{2} + 2 : \frac{df ( x )}{d x} = 6 x^{2} - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(1, 3) : y = 4 x - 1

y = 4 x - 1

What is the tangent of f(x)=2x^3-x^2+2,\at x=1 ?
The tangent of f(x)=2x^3-x^2+2,\at x=1 is y=4x-1