What is the tangent of f(x)=x^2,\at x=-5 ?

The tangent of f(x)=x^2,\at x=-5 is y=-10x-25

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tangent of f(x)=x^2,\at x=-5

tangent of

f (x) = x^{2}, at x = - 5

y = - 10 x - 25

Solution steps

Find the tangent point:

(- 5, 25)

Find the slope of

f (x) = x^{2} : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 10

Find the line with slope m=

- 10

and passing through

(- 5, 25) : y = - 10 x - 25

y = - 10 x - 25

What is the tangent of f(x)=x^2,\at x=-5 ?
The tangent of f(x)=x^2,\at x=-5 is y=-10x-25