What is the integral from 1 to 9 of sqrt(u+2) ?

The integral from 1 to 9 of sqrt(u+2) is (22sqrt(11))/3-2sqrt(3)

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integral from 1 to 9 of sqrt(u+2)

\int_{1}^{9} u + 2 d u

\frac{22 11}{3} - 23

Decimal

20.85781 \dots

Solution steps

\int_{1}^{9} u + 2 d u

Apply u-substitution

= \int_{3}^{11} v d v

Apply the Power Rule

= [\frac{2}{3} v^{\frac{3}{2}}]_{3}^{11}

Compute the boundaries:

\frac{22 11}{3} - 23

= \frac{22 11}{3} - 23

What is the integral from 1 to 9 of sqrt(u+2) ?
The integral from 1 to 9 of sqrt(u+2) is (22sqrt(11))/3-2sqrt(3)