derivative (7x^6+2x^3)^4

Lösung

ableitung von

(7 x^{6} + 2 x^{3})^{4}

4 (7 x^{6} + 2 x^{3})^{3} (42 x^{5} + 6 x^{2})

Schritte zur Lösung

\frac{d}{d x} ((7 x^{6} + 2 x^{3})^{4})

Wende die Kettenregel an:

4 (7 x^{6} + 2 x^{3})^{3} \frac{d}{d x} (7 x^{6} + 2 x^{3})

= 4 (7 x^{6} + 2 x^{3})^{3} \frac{d}{d x} (7 x^{6} + 2 x^{3})

\frac{d}{d x} (7 x^{6} + 2 x^{3}) = 42 x^{5} + 6 x^{2}

= 4 (7 x^{6} + 2 x^{3})^{3} (42 x^{5} + 6 x^{2})

t an g e n t x + 8

n = 0 \sum \infty 3^{n} 7^{- n}

\frac{\partial}{\partial y} (- x y^{2})

d er i v a t i v e y = 2 x e^{- 6 x} - 4 e^{x^{3}}

t an g e n t f (x) = \frac{10 x}{x ^{2} - 6}, (4, 4)