What is the tangent of f(x)=5e^x+x,\at x=0 ?

The tangent of f(x)=5e^x+x,\at x=0 is y=6x+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=5e^x+x,\at x=0

tangent of

f (x) = 5 e^{x} + x, at x = 0

y = 6 x + 5

Solution steps

Find the tangent point:

(0, 5)

Find the slope of

f (x) = 5 e^{x} + x : \frac{df ( x )}{d x} = 5 e^{x} + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(0, 5) : y = 6 x + 5

y = 6 x + 5

What is the tangent of f(x)=5e^x+x,\at x=0 ?
The tangent of f(x)=5e^x+x,\at x=0 is y=6x+5