What is area (-x+2),(-x^2-2x),-2,-1 ?

The answer to area (-x+2),(-x^2-2x),-2,-1 is 17/6

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area (-x+2),(-x^2-2x),-2,-1

area

(- x + 2), (- x^{2} - 2 x), - 2, - 1

\frac{17}{6}

Decimal

2.83333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{- 1} - x + 2 - (- x^{2} - 2 x) d x

Solve

\int_{- 2}^{- 1} - x + 2 - (- x^{2} - 2 x) d x : \frac{17}{6}

The area is:

= \frac{17}{6}

What is area (-x+2),(-x^2-2x),-2,-1 ?
The answer to area (-x+2),(-x^2-2x),-2,-1 is 17/6