What is (\partial)/(\partial x)(x^2+ye^x) ?

The answer to (\partial)/(\partial x)(x^2+ye^x) is 2x+ye^x

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(\partial)/(\partial x)(x^2+ye^x)

\frac{\partial}{\partial x} (x^{2} + y e^{x})

2 x + y e^{x}

Solution steps

\frac{\partial}{\partial x} (x^{2} + y e^{x})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y e^{x})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y e^{x}) = y e^{x}

= 2 x + y e^{x}

What is (\partial)/(\partial x)(x^2+ye^x) ?
The answer to (\partial)/(\partial x)(x^2+ye^x) is 2x+ye^x