What is the limit as x approaches 0+of (e^x-1)/x ?

The limit as x approaches 0+of (e^x-1)/x is 1

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limit as x approaches 0+of (e^x-1)/x

x \to 0 + lim (\frac{e ^{x} - 1}{x})

1

Solution steps

x \to 0 + lim (\frac{e ^{x} - 1}{x})

Apply L'Hopital's Rule

= x \to 0 + lim (\frac{e ^{x}}{1})

Plug in the value

x = 0

= \frac{e ^{0}}{1}

Simplify

= 1

What is the limit as x approaches 0+of (e^x-1)/x ?
The limit as x approaches 0+of (e^x-1)/x is 1