What is the derivative of f(x)=7e^{x^2-5x+6} ?

The derivative of f(x)=7e^{x^2-5x+6} is 7e^{x^2-5x+6}(2x-5)

What is the first derivative of f(x)=7e^{x^2-5x+6} ?

The first derivative of f(x)=7e^{x^2-5x+6} is 7e^{x^2-5x+6}(2x-5)

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derivative of

f (x) = 7 e^{x^{2} - 5 x + 6}

7 e^{x^{2} - 5 x + 6} (2 x - 5)

Solution steps

\frac{d}{d x} (7 e^{x^{2} - 5 x + 6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (e^{x^{2} - 5 x + 6})

Apply the chain rule:

e^{x^{2} - 5 x + 6} \frac{d}{d x} (x^{2} - 5 x + 6)

= e^{x^{2} - 5 x + 6} \frac{d}{d x} (x^{2} - 5 x + 6)

\frac{d}{d x} (x^{2} - 5 x + 6) = 2 x - 5

= 7 e^{x^{2} - 5 x + 6} (2 x - 5)

What is the derivative of f(x)=7e^{x^2-5x+6} ?
The derivative of f(x)=7e^{x^2-5x+6} is 7e^{x^2-5x+6}(2x-5)
What is the first derivative of f(x)=7e^{x^2-5x+6} ?
The first derivative of f(x)=7e^{x^2-5x+6} is 7e^{x^2-5x+6}(2x-5)