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Popular Calculus >

integral from 0 to 1 of (2x-3)

Solution

\int_{0}^{1} (2 x - 3) d x

Solution

- 2

Solution steps

\int_{0}^{1} 2 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 x d x - \int_{0}^{1} 3 d x

\int_{0}^{1} 2 x d x = 1

\int_{0}^{1} 3 d x = 3

= 1 - 3

Simplify

= - 2

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (2x-3) ?
The integral from 0 to 1 of (2x-3) is -2