What is (\partial)/(\partial x)(e^xcos(y)+yz) ?

The answer to (\partial)/(\partial x)(e^xcos(y)+yz) is e^xcos(y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(e^xcos(y)+yz)

\frac{\partial}{\partial x} (e^{x} cos (y) + yz)

e^{x} cos (y)

Solution steps

\frac{\partial}{\partial x} (e^{x} cos (y) + yz)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x} cos (y)) + \frac{\partial}{\partial x} (yz)

\frac{\partial}{\partial x} (e^{x} cos (y)) = cos (y) e^{x}

\frac{\partial}{\partial x} (yz) = 0

= cos (y) e^{x} + 0

Simplify

= e^{x} cos (y)

What is (\partial)/(\partial x)(e^xcos(y)+yz) ?
The answer to (\partial)/(\partial x)(e^xcos(y)+yz) is e^xcos(y)