derivative f(t)=sqrt(2t^2-t)

Lösung

ableitung von

f (t) = 2 t^{2} - t

\frac{4 t - 1}{2 2 t ^{2} - t}

Schritte zur Lösung

\frac{d}{d t} (2 t^{2} - t)

Wende die Kettenregel an:

\frac{1}{2 2 t ^{2} - t} \frac{d}{d t} (2 t^{2} - t)

= \frac{1}{2 2 t ^{2} - t} \frac{d}{d t} (2 t^{2} - t)

\frac{d}{d t} (2 t^{2} - t) = 4 t - 1

= \frac{1}{2 2 t ^{2} - t} (4 t - 1)

Vereinfache

\frac{1}{2 2 t ^{2} - t} (4 t - 1) : \frac{4 t - 1}{2 2 t ^{2} - t}

= \frac{4 t - 1}{2 2 t ^{2} - t}

y^{^{'}} + \frac{1}{x + 1} y = x^{- 2}

t an g e n t f (x) = (3 x - 2) (x + 4), (1, 5)

\frac{\partial}{\partial y} (x \cdot cos (y) \cdot sin (z))

x \to \infty lim (\frac{- x}{x})

\int \frac{( 3 x - 5 )}{x ^{2} + 4 x} d x