derivative 2log_{5}(t)

Lösung

ableitung von

2 lo g_{5} (t)

\frac{2}{ln ( 5 ) t}

Schritte zur Lösung

\frac{d}{d t} (2 lo g_{5} (t))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (lo g_{5} (t))

Wende die Derivat-Log-Regel an:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= 2 \cdot \frac{1}{t ln ( 5 )}

Vereinfache

2 \cdot \frac{1}{t ln ( 5 )} : \frac{2}{ln ( 5 ) t}

= \frac{2}{ln ( 5 ) t}

\int \frac{( 3 x - 2 ) ^{2} + ( 3 x + 2 ) ^{2}}{x ^{2}} d x

d er i v a t i v e \frac{cos ( 2 x )}{sin ( 2 x )}

\int (4 x^{5} + 3 x + 8) d x

f^{^{'}} (x) = 8 x^{3} - 6 x^{2} + 10 x - 9, f (1) = 24

ma c l a u r in 1 - x^{2}