y^{''}-8y^'+15y=4e^t

Lösung

y^{^{''}} - 8 y^{^{'}} + 15 y = 4 e^{t}

y = c_{1} e^{5 t} + c_{2} e^{3 t} + \frac{1}{2} e^{t}

Schritte zur Lösung

y^{''} (t) - 8 y^{'} (t) + 15 y = 4 e^{t}

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} e^{3 t} + \frac{1}{2} e^{t}

y = c_{1} e^{5 t} + c_{2} e^{3 t} + \frac{1}{2} e^{t}

\frac{\partial}{\partial x} (2 x + 3 e^{y} + x y)

in v erse l a pl a ce \frac{10 s}{( s + 1 ) ( s + 6 )}

\frac{d}{d x} \frac{4 ( y - x \frac{d y}{d x} )}{y ^{2}}

\int \frac{ln ^{2} ( x )}{3 x} d x

d er i v a t i v e y = ln (1 - x^{2})