What is the solution for (2xy+2x)dx-(1+x^4)dy=0 ?

The solution for (2xy+2x)dx-(1+x^4)dy=0 is y=e^{arctan(x^2)+c_{1}}-1

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(2xy+2x)dx-(1+x^4)dy=0

(2 x y + 2 x) d x - (1 + x^{4}) d y = 0

y = e^{a r c t a n (x^{2}) + c_{1}} - 1

Solution steps

(2 x y + 2 x) d x - (1 + x^{4}) d y = 0

Solve separable ODE:

y = e^{a r c t a n (x^{2}) + c_{1}} - 1

y = e^{a r c t a n (x^{2}) + c_{1}} - 1

What is the solution for (2xy+2x)dx-(1+x^4)dy=0 ?
The solution for (2xy+2x)dx-(1+x^4)dy=0 is y=e^{arctan(x^2)+c_{1}}-1