What is the tangent of f(x)=x^2+3x-3,\at x=2 ?

The tangent of f(x)=x^2+3x-3,\at x=2 is y=7x-7

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tangent of f(x)=x^2+3x-3,\at x=2

tangent of

f (x) = x^{2} + 3 x - 3, at x = 2

y = 7 x - 7

Solution steps

Find the tangent point:

(2, 7)

Find the slope of

f (x) = x^{2} + 3 x - 3 : \frac{df ( x )}{d x} = 2 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

Find the line with slope m=

7

and passing through

(2, 7) : y = 7 x - 7

y = 7 x - 7

What is the tangent of f(x)=x^2+3x-3,\at x=2 ?
The tangent of f(x)=x^2+3x-3,\at x=2 is y=7x-7