What is the d/(dt)(e^{t^2}) ?

The d/(dt)(e^{t^2}) is e^{t^2}*2t

What is the first d/(dt)(e^{t^2}) ?

The first d/(dt)(e^{t^2}) is e^{t^2}*2t

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\frac{d}{d t} (e^{t^{2}})

e^{t^{2}} \cdot 2 t

Solution steps

\frac{d}{d t} (e^{t^{2}})

Apply the chain rule:

e^{t^{2}} \frac{d}{d t} (t^{2})

= e^{t^{2}} \frac{d}{d t} (t^{2})

\frac{d}{d t} (t^{2}) = 2 t

= e^{t^{2}} \cdot 2 t