What is the solution for (2x+3)+(2y-2)(dy)/(dx)=0 ?

The solution for (2x+3)+(2y-2)(dy)/(dx)=0 is y=1+sqrt(-x^2-3x+c_{1)+1},y=1-sqrt(-x^2-3x+c_{1)+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(2x+3)+(2y-2)(dy)/(dx)=0

(2 x + 3) + (2 y - 2) \frac{d y}{d x} = 0

y = 1 + - x^{2} - 3 x + c_{1} + 1, y = 1 - - x^{2} - 3 x + c_{1} + 1

Solution steps

(2 x + 3) + (2 y - 2) \frac{d y}{d x} = 0

Solve separable ODE:

y = 1 + - x^{2} - 3 x + c_{1} + 1, y = 1 - - x^{2} - 3 x + c_{1} + 1

y = 1 + - x^{2} - 3 x + c_{1} + 1, y = 1 - - x^{2} - 3 x + c_{1} + 1

What is the solution for (2x+3)+(2y-2)(dy)/(dx)=0 ?
The solution for (2x+3)+(2y-2)(dy)/(dx)=0 is y=1+sqrt(-x^2-3x+c_{1)+1},y=1-sqrt(-x^2-3x+c_{1)+1}