What is the integral of 2+3x-4y^3 ?

The integral of 2+3x-4y^3 is 2x+(3x^2)/2-4y^3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2+3x-4y^3

\int 2 + 3 x - 4 y^{3} d x

2 x + \frac{3 x ^{2}}{2} - 4 y^{3} x + C

Solution steps

\int 2 + 3 x - 4 y^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x + \int 3 x d x - \int 4 y^{3} d x

\int 2 d x = 2 x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 4 y^{3} d x = 4 y^{3} x

= 2 x + \frac{3 x ^{2}}{2} - 4 y^{3} x

Add a constant to the solution

= 2 x + \frac{3 x ^{2}}{2} - 4 y^{3} x + C

What is the integral of 2+3x-4y^3 ?
The integral of 2+3x-4y^3 is 2x+(3x^2)/2-4y^3x+C