integral of (9e^x-9sqrt(x))

Lösung

\int (9 e^{x} - 9 x) d x

9 e^{x} - 6 x^{\frac{3}{2}} + C

Schritte zur Lösung

\int 9 e^{x} - 9 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 e^{x} d x - \int 9 x d x

\int 9 e^{x} d x = 9 e^{x}

\int 9 x d x = 6 x^{\frac{3}{2}}

= 9 e^{x} - 6 x^{\frac{3}{2}}

Füge eine Konstante zur Lösung hinzu

= 9 e^{x} - 6 x^{\frac{3}{2}} + C

d er i v a t i v e x^{3} e^{6 x^{3} + 8 x^{2} - 7}

d er i v a t i v e f (x) = \frac{f ( x )}{x ^{2} + 2}

\int_{1}^{16} \frac{4}{x} d x

x \to 0 lim (\frac{2 x}{x ^{2} - 5 x})

\frac{\partial}{\partial x} (4 x ln (x) y)