y^'=(-y)/x

Lösung

y^{^{'}} = \frac{- y}{x}

y = \frac{c _{1}}{x}

Schritte zur Lösung

y^{'} (x) = \frac{- y}{x}

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\frac{d}{d x} (\frac{x}{6 + x})

\frac{\partial}{\partial x} (\frac{1}{2 + x y ^{2}})

x \to 0 lim (\frac{x - x}{x})

\frac{d}{d x} ((x^{2} + 2)^{2})

\frac{\partial}{\partial y} (2 x y ln (y))