What is the tangent of f(x)=3x^3-x^2+1,(2,21) ?

The tangent of f(x)=3x^3-x^2+1,(2,21) is y=32x-43

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tangent of f(x)=3x^3-x^2+1,(2,21)

tangent of

f (x) = 3 x^{3} - x^{2} + 1, (2, 21)

y = 32 x - 43

Solution steps

Find the slope of

f (x) = 3 x^{3} - x^{2} + 1 : \frac{df ( x )}{d x} = 9 x^{2} - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 32

Find the line with slope m=

32

and passing through

(2, 21) : y = 32 x - 43

y = 32 x - 43

What is the tangent of f(x)=3x^3-x^2+1,(2,21) ?
The tangent of f(x)=3x^3-x^2+1,(2,21) is y=32x-43