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Popular Calculus >

integral from-1 to 3 of |x^2-2x|

Solution

\int_{- 1}^{3} x^{2} - 2 x d x

Solution

4

Solution steps

\int_{- 1}^{3} x^{2} - 2 x d x

Eliminate Absolutes

= \int_{- 1}^{0} x^{2} - 2 x d x + \int_{0}^{2} - x^{2} + 2 x d x + \int_{2}^{3} x^{2} - 2 x d x

\int_{- 1}^{0} x^{2} - 2 x d x = \frac{4}{3}

\int_{0}^{2} - x^{2} + 2 x d x = \frac{4}{3}

\int_{2}^{3} x^{2} - 2 x d x = \frac{4}{3}

= \frac{4}{3} + \frac{4}{3} + \frac{4}{3}

Simplify

\frac{4}{3} + \frac{4}{3} + \frac{4}{3} : 4

= 4

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 3 of |x^2-2x| ?
The integral from-1 to 3 of |x^2-2x| is 4