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Popular Calculus >

integral from 0 to 5 of (22+t)

Solution

\int_{0}^{5} (22 + t) d t

Solution

\frac{245}{2}

+1

Decimal

122.5

Solution steps

\int_{0}^{5} 22 + t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} 22 d t + \int_{0}^{5} t d t

\int_{0}^{5} 22 d t = 110

\int_{0}^{5} t d t = \frac{25}{2}

= 110 + \frac{25}{2}

Simplify

110 + \frac{25}{2} : \frac{245}{2}

= \frac{245}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of (22+t) ?
The integral from 0 to 5 of (22+t) is 245/2