derivative 2000+530(ln(x))

Lösung

ableitung von

2000 + 530 (ln (x))

\frac{530}{x}

Schritte zur Lösung

\frac{d}{d x} (2000 + 530 ln (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2000) + \frac{d}{d x} (530 ln (x))

\frac{d}{d x} (2000) = 0

\frac{d}{d x} (530 ln (x)) = \frac{530}{x}

= 0 + \frac{530}{x}

Vereinfache

= \frac{530}{x}

\int_{1}^{16} t ln (t) d t

p a r i t y x tan (x)

θ \to 0 lim (\frac{1 - cos ( θ )}{θ})

\int_{1}^{6} x^{2} d x

x \to 0 lim (\frac{1 - x}{2 + x})