derivative of \sqrt[4]{x+1}

Lösung

\frac{d}{d x} (4 x + 1)

\frac{1}{4 ( x + 1 ) ^{\frac{3}{4}}}

Schritte zur Lösung

\frac{d}{d x} (4 x + 1)

Wende die Kettenregel an:

\frac{1}{4 ( x + 1 ) ^{\frac{3}{4}}} \frac{d}{d x} (x + 1)

= \frac{1}{4 ( x + 1 ) ^{\frac{3}{4}}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= \frac{1}{4 ( x + 1 ) ^{\frac{3}{4}}} \cdot 1

Vereinfache

= \frac{1}{4 ( x + 1 ) ^{\frac{3}{4}}}

y^{^{'}} + \frac{2}{200 + t} y = 3

d er i v a t i v e (x - 4) (x + 5) (x + 4)

\frac{\partial}{\partial x} (6 y^{7} x^{5} - 5 y^{6} x^{4})

\int \frac{18}{1 - x ^{2}} d x

\int \frac{cos ^{3} ( 3 x )}{sin ^{5} ( 3 x )} d x