y^{''}+16y=-32sec(4t)

Lösung

y^{^{''}} + 16 y = - 32 sec (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) - 2 ln (cos (4 t)) cos (4 t) - 8 t sin (4 t)

Schritte zur Lösung

y^{''} (t) + 16 y = - 32 sec (4 t)

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t) - 2 ln (cos (4 t)) cos (4 t) - 8 t sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) - 2 ln (cos (4 t)) cos (4 t) - 8 t sin (4 t)

\int 3 y^{2} - 2 x d y

\int \frac{4 x}{x ^{4} - 12 x ^{2} + 45} d x

t an g e n t f (x) = 4 x^{2}, at x = 1

\frac{\partial}{\partial x} (x^{9 y})

\frac{\partial}{\partial u} (u \cdot cos (v))