What is the tangent of f(x)=ln(x^3-7),\at x=2 ?

The tangent of f(x)=ln(x^3-7),\at x=2 is y=12x-24

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tangent of f(x)=ln(x^3-7),\at x=2

tangent of

f (x) = ln (x^{3} - 7), at x = 2

y = 12 x - 24

Solution steps

Find the tangent point:

(2, 0)

Find the slope of

f (x) = ln (x^{3} - 7) : \frac{df ( x )}{d x} = \frac{3 x ^{2}}{x ^{3} - 7}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

Find the line with slope m=

12

and passing through

(2, 0) : y = 12 x - 24

y = 12 x - 24

What is the tangent of f(x)=ln(x^3-7),\at x=2 ?
The tangent of f(x)=ln(x^3-7),\at x=2 is y=12x-24