derivative x_{1}+x_{2}+x_{3}-12

解答

导数

x_{1} + x_{2} + x_{3} - 12

1

求解步骤

\frac{d}{d x _{1}} (x_{1} + x_{2} + x_{3} - 12)

将

x_{2}, x_{3}

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x _{1}} (x_{1}) + \frac{d}{d x _{1}} (x_{2}) + \frac{d}{d x _{1}} (x_{3}) - \frac{d}{d x _{1}} (12)

\frac{d}{d x _{1}} (x_{1}) = 1

\frac{d}{d x _{1}} (x_{2}) = 0

\frac{d}{d x _{1}} (x_{3}) = 0

\frac{d}{d x _{1}} (12) = 0

= 1 + 0 + 0 - 0

化简

= 1

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