tangent xy-picos(y)=3pi,(2,pi)

解答

切线

x y - π cos (y) = 3 π, (2, π)

y = - \frac{π}{2} x + 2 π

求解步骤

计算

x y - π cos (y) = 3 π

的斜率:

\frac{d y}{d x} = - \frac{y}{x + π sin ( y )}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{π}{2}

找到斜率 m=

- \frac{π}{2}

且穿过

(2, π)

的直线:

y = - \frac{π}{2} x + 2 π

y = - \frac{π}{2} x + 2 π

\frac{\partial}{\partial t} (\frac{2 r + s}{t})

\frac{d}{d x} (- 12 sin (6 x))

d er i v a t i v e y = (3 x + 4)^{2}

x \to 0 lim (\frac{x ^{2} + 5}{3 ^{x}})

n = 1 \sum \infty (- 1)^{n} 2^{- n}