What is the derivative of y=((x+b)(x-a))/((x-b)) ?

The derivative of y=((x+b)(x-a))/((x-b)) is (x^2-2bx-b^2+2ba)/((x-b)^2)

What is the first derivative of y=((x+b)(x-a))/((x-b)) ?

The first derivative of y=((x+b)(x-a))/((x-b)) is (x^2-2bx-b^2+2ba)/((x-b)^2)

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derivative of

y = \frac{( x + b ) ( x - a )}{( x - b )}

\frac{x ^{2} - 2 b x - b ^{2} + 2 ba}{( x - b ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( x + b ) ( x - a )}{x - b})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( ( x + b ) ( x - a ) ) ( x - b ) - \frac{d}{d x} ( x - b ) ( x + b ) ( x - a )}{( x - b ) ^{2}}

\frac{d}{d x} ((x + b) (x - a)) = 2 x + b - a

\frac{d}{d x} (x - b) = 1

= \frac{( 2 x + b - a ) ( x - b ) - 1 \cdot ( x + b ) ( x - a )}{( x - b ) ^{2}}

Simplify

\frac{( 2 x + b - a ) ( x - b ) - 1 \cdot ( x + b ) ( x - a )}{( x - b ) ^{2}} : \frac{x ^{2} - 2 b x - b ^{2} + 2 ba}{( x - b ) ^{2}}

= \frac{x ^{2} - 2 b x - b ^{2} + 2 ba}{( x - b ) ^{2}}

What is the derivative of y=((x+b)(x-a))/((x-b)) ?
The derivative of y=((x+b)(x-a))/((x-b)) is (x^2-2bx-b^2+2ba)/((x-b)^2)
What is the first derivative of y=((x+b)(x-a))/((x-b)) ?
The first derivative of y=((x+b)(x-a))/((x-b)) is (x^2-2bx-b^2+2ba)/((x-b)^2)