d/(dθ)(θcos(θ)-sin(θ))

解答

\frac{d}{d θ} (θ cos (θ) - sin (θ))

- θ sin (θ)

求解步骤

\frac{d}{d θ} (θ cos (θ) - sin (θ))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (θ cos (θ)) - \frac{d}{d θ} (sin (θ))

\frac{d}{d θ} (θ cos (θ)) = cos (θ) - θ sin (θ)

\frac{d}{d θ} (sin (θ)) = cos (θ)

= cos (θ) - θ sin (θ) - cos (θ)

化简

= - θ sin (θ)

\frac{d}{d x} (e^{x + 2 y})

\frac{d}{d x} (ln (\frac{( 2 x - 1 )}{x - 1}))

\int e^{s i n (x)} \cdot cos (x) d x

\int \frac{x - 11}{x ^{2} + 3 x - 4} d x

n = 0 \sum \infty \frac{4 ^{n}}{n !}