(\partial)/(\partial x)(ln(x^2+yx))

Lösung

\frac{\partial}{\partial x} (ln (x^{2} + y x))

\frac{2 x + y}{x ^{2} + x y}

Schritte zur Lösung

\frac{\partial}{\partial x} (ln (x^{2} + y x))

Behandle

y

als Konstante

Wende die Kettenregel an:

\frac{1}{x ^{2} + y x} \frac{\partial}{\partial x} (x^{2} + y x)

= \frac{1}{x ^{2} + y x} \frac{\partial}{\partial x} (x^{2} + y x)

\frac{\partial}{\partial x} (x^{2} + y x) = 2 x + y

= \frac{1}{x ^{2} + y x} (2 x + y)

Vereinfache

\frac{1}{x ^{2} + y x} (2 x + y) : \frac{2 x + y}{x ^{2} + x y}

= \frac{2 x + y}{x ^{2} + x y}

a re a 10 - 7 x, x^{2} - 20, x = 0

\int (3 x + 2) 3 3 x^{2} + 4 x d x

\frac{d}{d x} (ln (x^{y}))

\int u^{- 2} (2 u^{4} + 3 u^{2} - 2 u^{- 3}) d u

\frac{d}{d x} (\frac{3 x - 4}{2 x ^{2} + 5})