What is the derivative of 3^x-1 ?

The derivative of 3^x-1 is ln(3)*3^x

What is the first derivative of 3^x-1 ?

The first derivative of 3^x-1 is ln(3)*3^x

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\frac{d}{d x} (3^{x} - 1)

ln (3) \cdot 3^{x}

Solution steps

\frac{d}{d x} (3^{x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3^{x}) - \frac{d}{d x} (1)

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

\frac{d}{d x} (1) = 0

= 3^{x} ln (3) - 0

Simplify

= ln (3) \cdot 3^{x}

What is the derivative of 3^x-1 ?
The derivative of 3^x-1 is ln(3)*3^x
What is the first derivative of 3^x-1 ?
The first derivative of 3^x-1 is ln(3)*3^x