integral of arcsin(x+2)

Lösung

\int arcsin (x + 2) d x

x arcsin (x + 2) + - x^{2} - 4 x - 3 + 2 arcsin (x + 2) + C

Schritte zur Lösung

\int arcsin (x + 2) d x

Wende die partielle Integration an

= x arcsin (x + 2) - \int \frac{x}{- x ^{2} - 4 x - 3} d x

\int \frac{x}{- x ^{2} - 4 x - 3} d x = - - x^{2} - 4 x - 3 - 2 arcsin (x + 2)

= x arcsin (x + 2) - (- - x^{2} - 4 x - 3 - 2 arcsin (x + 2))

Vereinfache

= x arcsin (x + 2) + - x^{2} - 4 x - 3 + 2 arcsin (x + 2)

Füge eine Konstante zur Lösung hinzu

= x arcsin (x + 2) + - x^{2} - 4 x - 3 + 2 arcsin (x + 2) + C

in v erse l a pl a ce \frac{1}{s ^{3} - 2 s ^{2} + 3 s}

p a r i t y y = arcsinh (tan (x))

t an g e n t f (x) = x cos (x), at x = \frac{3 π}{2}

\frac{d}{d x} (\frac{13}{x})

in v erse l a pl a ce \frac{1}{( s ^{2} - 1 ) ^{2}}