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Popular Calculus >

y^'=sqrt(x^9+1)

Solution

y^{^{'}} = x^{9} + 1

Solution

y = \int x^{9} + 1 d x

Solution steps

y^{'} (x) = x^{9} + 1

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{9} + 1 d x

y = \int x^{9} + 1 d x

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Frequently Asked Questions (FAQ)

What is the solution for y^'=sqrt(x^9+1) ?
The solution for y^'=sqrt(x^9+1) is y=integral of sqrt(x^9+1)