What is the derivative of y=3e^{3e^x+x} ?

The derivative of y=3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)

What is the first derivative of y=3e^{3e^x+x} ?

The first derivative of y=3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)

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derivative of

y = 3 e^{3 e^{x} + x}

3 e^{3 e^{x} + x} (3 e^{x} + 1)

Solution steps

\frac{d}{d x} (3 e^{3 e^{x} + x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (e^{3 e^{x} + x})

Apply the chain rule:

e^{3 e^{x} + x} \frac{d}{d x} (3 e^{x} + x)

= e^{3 e^{x} + x} \frac{d}{d x} (3 e^{x} + x)

\frac{d}{d x} (3 e^{x} + x) = 3 e^{x} + 1

= 3 e^{3 e^{x} + x} (3 e^{x} + 1)

What is the derivative of y=3e^{3e^x+x} ?
The derivative of y=3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)
What is the first derivative of y=3e^{3e^x+x} ?
The first derivative of y=3e^{3e^x+x} is 3e^{3e^x+x}(3e^x+1)