derivative of 6cos(2x-e^{-x})

Lösung

\frac{d}{d x} (6 cos (2 x) - e^{- x})

- 12 sin (2 x) + e^{- x}

Schritte zur Lösung

\frac{d}{d x} (6 cos (2 x) - e^{- x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 cos (2 x)) - \frac{d}{d x} (e^{- x})

\frac{d}{d x} (6 cos (2 x)) = - 12 sin (2 x)

\frac{d}{d x} (e^{- x}) = - e^{- x}

= - 12 sin (2 x) - (- e^{- x})

Vereinfache

= - 12 sin (2 x) + e^{- x}

t an g e n t f (x) = 2 x^{3} + 7 x^{2} - 8 x - 3, at x = - 1

x \to 1 - lim (1 - x - [x] - [1 - x])

x \to 4 - lim (\frac{1}{( x - 4 ) ^{2}})

d er i v a t i v e f (x) = x^{(7)} - 3 e^{(3 x)}

x \to 0 lim ((1 + 4 x)^{\frac{1}{x}})