derivative of \sqrt[3]{2x-7}

Lösung

\frac{d}{d x} (3 2 x - 7)

\frac{2}{3 ( 2 x - 7 ) ^{\frac{2}{3}}}

Schritte zur Lösung

\frac{d}{d x} (3 2 x - 7)

Wende die Kettenregel an:

\frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x - 7)

= \frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x - 7)

\frac{d}{d x} (2 x - 7) = 2

= \frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \cdot 2

Vereinfache

\frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \cdot 2 : \frac{2}{3 ( 2 x - 7 ) ^{\frac{2}{3}}}

= \frac{2}{3 ( 2 x - 7 ) ^{\frac{2}{3}}}

\int \frac{x ^{'}}{x ^{2}} d x

\frac{\partial}{\partial x} (2 x y - 3 x z^{2})

\int 5 sin^{4} (x co) s^{2} x d x

\frac{d}{d x} (\frac{x ^{2} + 2 x}{3 x + 6})

x \to - 1 lim (x^{3} - 2)