What is the derivative of-(e^{x-1}(x-3)/((x-1)^3)) ?

The derivative of-(e^{x-1}(x-3)/((x-1)^3)) is -(e^{x-1}(x^2-6x+11))/((x-1)^4)

What is the first derivative of-(e^{x-1}(x-3)/((x-1)^3)) ?

The first derivative of-(e^{x-1}(x-3)/((x-1)^3)) is -(e^{x-1}(x^2-6x+11))/((x-1)^4)

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\frac{d}{d x} (- \frac{e ^{x - 1} ( x - 3 )}{( x - 1 ) ^{3}})

- \frac{e ^{x - 1} ( x ^{2} - 6 x + 11 )}{( x - 1 ) ^{4}}

Solution steps

\frac{d}{d x} (- \frac{e ^{x - 1} ( x - 3 )}{( x - 1 ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{e ^{x - 1} ( x - 3 )}{( x - 1 ) ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - \frac{\frac{d}{d x} ( e ^{x - 1} ( x - 3 ) ) ( x - 1 ) ^{3} - \frac{d}{d x} ( ( x - 1 ) ^{3} ) e ^{x - 1} ( x - 3 )}{( ( x - 1 ) ^{3} ) ^{2}}

\frac{d}{d x} (e^{x - 1} (x - 3)) = e^{x - 1} x - 2 e^{x - 1}

\frac{d}{d x} ((x - 1)^{3}) = 3 (x - 1)^{2}

= - \frac{( e ^{x - 1} x - 2 e ^{x - 1} ) ( x - 1 ) ^{3} - 3 ( x - 1 ) ^{2} e ^{x - 1} ( x - 3 )}{( ( x - 1 ) ^{3} ) ^{2}}

Cancel

\frac{( e ^{x - 1} x - 2 e ^{x - 1} ) ( x - 1 ) ^{3} - 3 ( x - 1 ) ^{2} e ^{x - 1} ( x - 3 )}{( ( x - 1 ) ^{3} ) ^{2}} : \frac{e ^{x - 1} ( x ^{2} - 6 x + 11 )}{( x - 1 ) ^{4}}

= - \frac{e ^{x - 1} ( x ^{2} - 6 x + 11 )}{( x - 1 ) ^{4}}

What is the derivative of-(e^{x-1}(x-3)/((x-1)^3)) ?
The derivative of-(e^{x-1}(x-3)/((x-1)^3)) is -(e^{x-1}(x^2-6x+11))/((x-1)^4)
What is the first derivative of-(e^{x-1}(x-3)/((x-1)^3)) ?
The first derivative of-(e^{x-1}(x-3)/((x-1)^3)) is -(e^{x-1}(x^2-6x+11))/((x-1)^4)