What is the derivative of 6x^3-4x^2+5x ?

The derivative of 6x^3-4x^2+5x is 18x^2-8x+5

What is the first derivative of 6x^3-4x^2+5x ?

The first derivative of 6x^3-4x^2+5x is 18x^2-8x+5

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\frac{d}{d x} (6 x^{3} - 4 x^{2} + 5 x)

18 x^{2} - 8 x + 5

Solution steps

\frac{d}{d x} (6 x^{3} - 4 x^{2} + 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{3}) - \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (5 x)

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (5 x) = 5

= 18 x^{2} - 8 x + 5

What is the derivative of 6x^3-4x^2+5x ?
The derivative of 6x^3-4x^2+5x is 18x^2-8x+5
What is the first derivative of 6x^3-4x^2+5x ?
The first derivative of 6x^3-4x^2+5x is 18x^2-8x+5